Refactored functions from 1 to 5
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@ -1,5 +1,5 @@
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% Algorithm 1: Outer Product Gaussian Elimination (Alg. 3.2.1)
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function A = outer_product_gaussian_elimination(A)
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function A = Alg1_outer_product_gaussian_elimination(A)
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[n, m] = size(A);
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if n ~= m
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@ -14,4 +14,6 @@ end
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rows = k + 1 : n;
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A(rows, k) = A(rows, k)/A(k, k);
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A(rows, rows) = A(rows, rows) - A(rows, k) * A(k, rows);
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end
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end
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end
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@ -1,4 +1,4 @@
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function [P, Q, L, U] = gaussian_elimination_with_complete_pivoting(A)
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function [P, Q, L, U] = Alg2_gaussian_elimination_with_complete_pivoting(A)
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[n, m] = size(A);
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if n ~= m
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@ -1,5 +1,5 @@
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% Algorithm 3: Forward Substitution (Alg. 3.1.1)
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function b = forward_substitution(L, b)
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function b = Alg3_forward_substitution(L, b)
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[n, m] = size(L);
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if n ~= m
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@ -1,5 +1,5 @@
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% Argorithm 4: Back Substitution (Alg. 3.1.2)
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function b = back_substitution(U,b)
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function b = Alg4_back_substitution(U,b)
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[n, m] = size(U);
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if n ~= m
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@ -1,6 +1,6 @@
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% Algorithm 5: Gauss-Jordan Elimination
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% Algorithm 5: Gauss-Jordan Elimination (Alg.
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% Argument A is an augmented matrix
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function A = gauss_jordan_elimination(A)
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function A = Alg5_gauss_jordan_elimination(A)
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% M – rows, N – columns
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@ -7,7 +7,7 @@ A = [2, -1, 0, 0;
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b = [0;0;0;5];
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B = outer_product_gaussian_elimination(A);
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B = Alg1_outer_product_gaussian_elimination(A);
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U = triu(B);
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L = tril(B, -1);
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x = back_substitution(U, b);
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@ -23,7 +23,7 @@ b = [0;0;0;5];
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B = gauss_jordan_elimination([A b])
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[P, Q, L, U] = gaussian_elimination_with_complete_pivoting(A);
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[P, Q, L, U] = Alg2_gaussian_elimination_with_complete_pivoting(A);
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b = P*b;
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% Ly = b and Ux = y
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@ -40,7 +40,7 @@ A = [1, 1, 1;
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b = [1;2;1];
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[P, Q, L, U] = gaussian_elimination_with_complete_pivoting(A);
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[P, Q, L, U] = Alg2_gaussian_elimination_with_complete_pivoting(A);
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b = P*b;
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% Ly = b and Ux = y
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@ -69,11 +69,13 @@ A = [2, 1, 2;
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1, 2, 3;
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4, 1, 2];
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[P, Q, L, U] = gaussian_elimination_with_complete_pivoting(A);
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[P, Q, L, U] = Alg2_gaussian_elimination_with_complete_pivoting(A);
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I = P*eye(3);
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% Ly = b and Ux = y
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y = forward_substitution(L, I);
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X = Q*back_substitution(U, y)
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inv(A)
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inv(A)
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%% Problem 6
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